If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2x^2+3x-999=0
a = 2; b = 3; c = -999;
Δ = b2-4ac
Δ = 32-4·2·(-999)
Δ = 8001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8001}=\sqrt{9*889}=\sqrt{9}*\sqrt{889}=3\sqrt{889}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{889}}{2*2}=\frac{-3-3\sqrt{889}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{889}}{2*2}=\frac{-3+3\sqrt{889}}{4} $
| |z−3|=0 | | 3.2(x-1)=5.12 | | 3x-23÷4=-2 | | -11=35x=24 | | -12x+3=231 | | -6+2x=3x+1-x-7 | | -(-5/4x+3)-3x=-7(-1/4x+2) | | 7(x-5)=6(x+15) | | (3x-23)÷4=-2 | | b/3+5=3/2+1/3 | | .50x×15=25×.25x | | (9i)/(-10-3i)=0 | | -2n^+7n+15=0 | | b/3*5=3/2+1/3 | | 31/2x+5=21/4+6 | | 9p=-5(p-6) | | (5z+4=)+(3z+6=) | | -4+p/8=-5 | | 3x-2x+6=-22 | | 22+5w=62 | | -2n-6=-46 | | 11/4x+5=6 | | -0.8x^2+24x-90=0 | | 58=q/8+49 | | 10x+3+1-x=13x-3+7x | | -12+5b=23 | | 2x-15=x-5+5 | | x-125,000=0.25 | | 5+8x=356 | | 3=-8+15y | | 35w+55-10w+28w=75-5w+12 | | 7-9v-3=22 |